Pelumiawobodu Pelumiawobodu
  • 03-02-2020
  • Mathematics
contestada

Please help me solve this 5^2x=7^x+1

Respuesta :

profarouk profarouk
  • 03-02-2020

Answer:

[tex]x=\frac{ln7}{2ln5-ln7}[/tex]

Step-by-step explanation:

5^2x=7^x+1 ⇔ ln5^2x = ln7^x+1 ⇔ 2xln5 = (x+1)ln7 ⇔ (2ln5-ln7)x = ln7

⇔ x = ln7/(2ln5-ln7)

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estelallop
estelallop estelallop
  • 03-02-2020
it’s gonna translate to 25x=7x+1
so then 18x=1
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