ikang24601 ikang24601
  • 05-03-2020
  • Mathematics
contestada

The roots of the quadratic equation z^2 + az + b = 0 are -7 + 2i and -7 - 2i. What is a+b?

Respuesta :

spotify2joseph spotify2joseph
  • 05-03-2020

Answer:

a+b=249/14

Step-by-step explanation:

z1= [-a+sqrt(a^2-4ab)]/2

z1= [-a-sqrt(a^2-4ab)]/2

--------------------------------------------------

z1= -a/2+[sqrt(a^2-4ab)]/2

then,

-a/2=-7

so, a=14

a^2-4ab= -16

b=(a^2+16)/(4a)

b=53/24

therefore, a+b= 249/14

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