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  • 03-06-2020
  • Mathematics
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How would you solve dy/dx = 4x - 2, y(-1) = 1 using differential equations?

Respuesta :

ahmedelkazaz42
ahmedelkazaz42 ahmedelkazaz42
  • 03-06-2020

Answer:

y=2(x square)-2x-3

Step-by-step explanation:

Let dy with y varibles in a hand

And dx with x variables on the other hand

dy=(4x-2)dx

Then by integration

y=2(square x)-2x+constant

Then substitute by x=-1 and y=1 to find the value of the constant

1=2(1)-2(-1)+ constant

Then constant=-3

Then the equation is

y=2(x square)-2x-3

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