amanda798 amanda798
  • 01-07-2020
  • Mathematics
contestada

Any help would be greatly appreciated

Any help would be greatly appreciated class=

Respuesta :

Alfpfeu
Alfpfeu Alfpfeu
  • 01-07-2020

Answer:

[tex]\boxed{\df \ \ \ \dfrac{b^7}{3} \ \ \ }[/tex]

Step-by-step explanation:

[tex]\dfrac{9h^2b^8}{27h^2b}=\dfrac{h^{2-2}b^{8-1}}{3}=\dfrac{b^7}{3}[/tex]

as 27=9*3

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