01-06-2021
Chemistry

contestada

How can I solve this pls

How can I solve this pls class=

Respuesta :

kjashanpreet2004 kjashanpreet2004

01-06-2021

Explanation:

A= Mercury (ll) oxide

B= Mercury and Oxygen

This is an oxidation-reduction (redox) reaction:

2 HgII + 4 e- → 2 Hg0

(reduction)

2 O-II - 4 e- → 2 O0

(oxidation)

HgO is an oxidizing agent, HgO is a reducing agent.

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KylaLake KylaLake

01-06-2021

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