mandylewis6789
mandylewis6789 mandylewis6789
  • 01-03-2017
  • Mathematics
contestada

How many three-digit numbers greater than 200 can be formed from the digits 1, 2, 6, 7, and 9, if the digits can be repeated?

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siegman29 siegman29
  • 01-03-2017
. You have four choices for the first digit (2,6,7 or 9) because if the first digit is one, the number will be less than 200. You have five choices each for the second and third digit. 4*5*5=100 possible numbers.

2. This is simply 10C3=(10*9*8)/(3*2*1)=120.
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hiiamshyan
hiiamshyan hiiamshyan
  • 04-03-2017
12 for each so 12x5=60
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