naymacruz naymacruz
  • 02-08-2017
  • Mathematics
contestada

Solve 5^x=81. 2
Round to the nearest ten-thousandth.

X≈????

Respuesta :

irspow
irspow irspow
  • 02-08-2017
Is that 5^x=81.2?

5^x=81.2  take the natural log of both sides

xln5=ln81.2  divide both sides by ln5

x=ln81.2/ln5

x≈2.7320  (to nearest ten-thousandth)

If you just meant 5^x=81, the process is the same

5^x=81  take the natural log of both sides

xln5=ln81  divide both sides by ln5

x=ln81/ln5

x≈2.7304  (to nearest ten-thousandth)


Answer Link

Otras preguntas

Marvin drove 310 miles in 5 hours. At this same rate, how far could he travel in 2 hours? a. 105 miles b. 124 miles c. 155 miles d. 170 miles e. 200 miles
Solve the inequality
Plot A(2,3) and B(2,5). What is the midpoint of points A and B?
Solve The Equation. 6x-6= -9(4x-1/3)
For each function f, find f^-1 and f^-1(5). f={(-1,5), (0,0), (2,6)}
How the federal government supported nationalism in their intersections with the states
Evaluate the expression 8 x 1. 5
Amy thinks of three numbers, which she calls a, b and c. The ratio a: cis 4: 3. The ratio b: cis 7:5. The median of a, b and c is 80. Work out the values of a,
Amy thinks of three numbers, which she calls a, b and c. The ratio a: cis 4: 3. The ratio b: cis 7:5. The median of a, b and c is 80. Work out the values of a,
The value of 3 in 6,300 is _____ times the value of 3 in 530.