flowerdaisy9990 flowerdaisy9990

01-10-2017
Mathematics

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The length of a rectangle is 4 yd longer than its width. if the perimeter of the rectangle is 32 yd, find its area.

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ghanami ghanami

01-10-2017

hello:
let : x the length and : y the width
2(x+y) the perimeter and ; xy the area.
x = y +4...(1)
2(x+y) = 32 ...(2)
subsct x by (1) in (2) :
2(y+4 +y) = 32
2y +8 +2y = 32
4y =24
y = 24/4 = 6 yd
x= 6+4=10 yd
the area is : 60 yd²

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